Arrays.parallelPrefix metodu

Giriş

Açıklaması şöyle. Yani her elemana bir önceki elemana uygulanmış metot çıktısını uygular

Cumulates, in parallel, each element of the given array in place, using the supplied function. For example if the array initially holds [2, 1, 0, 3] and the operation performs addition, then upon return the array holds [2, 3, 3, 6]. Parallel prefix computation is usually more efficient than sequential loops for large arrays.

Örnek

Şöyle yaparız

int[] numbers = {1, 2, 3, 4, 5};
Arrays.parallelPrefix(numbers, (x, y) -> x * y); // 2nd arg is lambda 

// The original array is now updated
System.out.println(Arrays.toString(numbers));

// Output: {1, 2, 6, 24, 120}

Örnek

Şöyle yaparız

int[] nums = {1, 1, 1, 2, 3};
Arrays.parallelPrefix(nums,Integer::sum);
System.out.println(Arrays.toString(nums));

//[1, 2, 3, 5, 8]

int[] nums = {1, 2, 3, 4, 5};
Arrays.parallelPrefix(nums, (i,j) -> i*j);
System.out.println(Arrays.toString(nums));

//[1, 2, 6, 24, 120]